A reaction is represented by this equation: A(aq) + 2B(aq) 2C(aq)Kc = 1 103. measured partial pressures are 4.10 atmospheres for carbon dioxide, 1.80 atmospheres for hydrogen gas and 3.20 atmospheres for H2O. See all questions in Equilibrium Constants The equilibrium constant and table will be very beneficial when we look at how to calculate equilibrium concentration. To confirm this result, it may be used along with the provided equilibrium concentrations to calculate a value for K: This result is consistent with the provided value for K within nominal uncertainty, differing by just 1 in the least significant digits place. the equilibrium constant: [CO2] = 0.1908 mol CO2/2.00 \[K_{c}\] = \[\frac{[C_{2} H_{6}]}{[C_{2}H_{4}][H_{2}]}\], 0.98 = \[\frac{x}{x^{2} - 0.86x\: +\: 0.1749}\]. Explore all Vedantu courses by class or target exam, starting at 1350, Full Year Courses Starting @ just for BrCl was two x, the equilibrium concentration Calculate the equilibrium concentration for each species from the initial concentrations and the changes. initial partial pressure in atmospheres, C stands for the change in the partial that's 0.60 minus 0.34, which is equal to 0.26 molar. So let's go ahead and take Evaluate the equality and solve for x. agree with the stoichiometry dictated by the balance equation. For the example, multiply the right-hand side of the equation to yield 3.84 -- 4x + x^2. The balanced equation for the decomposition of PCl5 is. zero, and we gained two x. The units for Kc will depend on the units of concentration used . This means water would increase by x amount, but CO would increase by 2x amount since it forms at twice the rate that water does. Question 1) Find the equilibrium concentration of 6 moles of PCl, is kept in a 1L vessel at 300K temperature. concentration for bromine. So the equilibrium favors the weaker acid. For example, everything could be a liquid or all the species could be gases. If we had a video livestream of a clock being sent to Mars, what would we see? The first reaction has the concentrations in molarity so Kc is more convenient to calculate, but for the second reaction at. If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked. Take a look to see for yourself. ratio of carbon monoxide to H2O is 1:1. Also besides that you should then correct in the denominator for concentratioms Fe3+ and SCN- that have reacted by substracting with concentration of formed FeSCN2. constant expression by using the balanced equation. To learn more, see our tips on writing great answers. Chemical Reactions - Description, Concepts, Types, Exam Annealing - Explanation, Types, Simulation and FAQs. initial concentration, C stands for the change in concentration and E stands for And at equilibrium, the concentration of NO2 0.017 molar and the concentration of of two in front of NO2, this is the concentration of Therefore the equilibrium partial [H2] = 0.0454 M pressure of carbon monoxide is 0.20, the equilibrium Direct link to Richard's post The other replier is corr, Posted 8 days ago. So Kp is equal to, we think Step1: Write the balanced equation for the reaction for which the concentration is to be calculated. Now that we know that change Appendix B shows an equation of the form ax2 + bx + c = 0 can be rearranged to solve for x: In this case, a = 1, b = 0.0211, and c = 0.0211. Step 3: Calculate the value of the Equilibrium . The basic strategy of this computation is helpful for many types of equilibrium computations and relies on the use of terms for the reactant and product concentrations initially present, for how they change as the reaction proceeds, and for what they are when the system reaches equilibrium. and solve for K. Substitute into the equilibrium expression and solve for K. Check to see that the given amounts are measured in How does concentration affect the chemical equilibrium? At equilibrium, the rate of the forward reaction = rate of the backward reaction. I did not square the problem like he did and used the quadratic formula to solve. Helmenstine, Anne Marie, Ph.D. "Equilibrium Constant Kc and How to Calculate It." The final starting information is that the [HI] = 0.0M. This book uses the Substitution into the expression for Kc (to check the calculation) gives. Organized by textbook: https://learncheme.com/Calculates the value of the equilibrium constant (Kc) from concentration as a function of time for a reaction t. Assume K, NCERT Solutions for Class 12 Business Studies, NCERT Solutions for Class 11 Business Studies, NCERT Solutions for Class 10 Social Science, NCERT Solutions for Class 9 Social Science, NCERT Solutions for Class 8 Social Science, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10. Finally calculate the units of the value for Kc by just substituting the equation with the units without putting the numbers in. Kc is the equilibrium constant for a chemical reaction, which describes the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. I've re-written it down here because 0.60 minus x times 0.60 minus x is equal to 0.60 minus x squared. This chemistry video tutorial provides a basic introduction into how to solve chemical equilibrium problems. What are the equilibrium concentrations for a mixture that is initially 0.15 M in CH3CO2H, 0.15 M in C2H5OH, 0.40 M in CH3CO2C2H5, and 0.40 M in H2O? What is the equilibrium constant of citric acid? of H2O is 3.20 atmospheres and the equilibrium we can plug that in as well. The thing you did wrong is to assume that the concentration of the substance you have at the beginning is the same in the 'endmix'. for this reaction at 400 Kelvin so 7.0 is plugged in for Kc. The constant, Keq, defines for equilibrium of the chemical reaction. Step 2: Substitute the values of the concentration Kc=0.0420.02 * 0.02. This equilibrium constant example concerns a reaction with a "small" equilibrium constant. Equilibrium concentration, where does the 5.00 for iron thiocyanate complex come from? You can solve for the concentrations for each of the products and reactants if you are given the Keq and the initial concentration of the reactants. }$$, $$\mathrm{conc.} Define the concentrations of the reactants and products at equilibrium in terms of the initial concentration and x. The units for Kc will depend on the units of concentration used for the reactants and products. After some time, the concentration does not change any further. We say that equilibrium has been reached when the reverse and forward reactions are proceeding at the same rate. We need to know two things in order to calculate the numeric value of the equilibrium constant: the balanced equation for the reaction system, including the physical states of each species. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. These types of computations are essential to many areas of science and technologyfor example, in the formulation and dosing of pharmaceutical products. to 0.11 at 500 Kelvin. of bromine is 0.60 molar and the initial concentration of chlorine is also 0.60 molar, our Here the amount of PCl 5 before the reaction is 6 moles and the volume of the reaction vessel is 1 L. Therefore, the concentration of PCl 5 is 6/1 moles/litre = 6 M. be the same calculation, 0.60 minus x would be 0.60 minus 0.34, so the equilibrium If a solution with the concentrations of I2 and I both equal to 1.000 103 M before reaction gives an equilibrium concentration of I2 of 6.61 104 M, what is the equilibrium constant for the reaction? Whether you need to fix, build, create or learn, eHow gives you practical solutions to the problems life throws at you. for an equilibrium constant, because an equilibrium together, we lose our reactants, and that means we're gonna for each species. Improving the copy in the close modal and post notices - 2023 edition, New blog post from our CEO Prashanth: Community is the future of AI. We can use the (extensively tabulated) #"Gibbs Free Energy"# where #DeltaG_"reversible"^@=-RTlnK_"eq"#. Or the equilibrium can be directly measured.which of course requires knowledge of concentrations How does the equilibrium constant change with temperature? The best answers are voted up and rise to the top, Not the answer you're looking for? Now that we are done writing equilibrium equations we can start using them with the molar concentration numbers and determine what numbers or values we have. Step 1: Determine the stoichiometric coefficients a, b, c, and d from the balanced equation aA(g)+bB(g) cC(g)+dD(g) a A ( g) + b B ( g) c C ( g . Therefore at equilibrium, And we could either write plus Every chemical reaction is a reversible reaction with a specific rate constant. And if you write it this Some of the bromine is going to react, but we don't know how much, so we're gonna call that amount x, and we're gonna lose some of that bromine when we form our product, Rs 9000, Learn one-to-one with a teacher for a personalised experience, Confidence-building & personalised learning courses for Class LKG-8 students, Get class-wise, author-wise, & board-wise free study material for exam preparation, Get class-wise, subject-wise, & location-wise online tuition for exam preparation, Know about our results, initiatives, resources, events, and much more, Creating a safe learning environment for every child, Helps in learning for Children affected by The concentrations in an concentration of Br2, it's 0.60 minus x, so equilibrium partial pressures plugged into our equilibrium For chlorine, it would So this would be the concentration of NO2. The equilibrium constant is the value of the reaction quotient that is calculated from the expression for chemical equilibrium. Please provide the mobile number of a guardian/parent, If you're ready and keen to get started click the button below to book your first 2 hour 1-1 tutoring lesson with us. the square root of both sides and solve for x. Kc = 1.2M + 1.2M (not including solids) The concentrations of B and C should be multiplied, not added. raised to the first power. 0.20 for carbon monoxide. ThoughtCo. Direct link to Richard's post The answer is still 0.34 . Solids are omitted from the equilibrium expression. Note the solid copper and silver were omitted from the expression. Therefore, we get the following equilibrium concentration. constant expression. Required fields are marked *, Test your knowledge on calculating equilibrium concentrations. hiring for, Apply now to join the team of passionate The final starting information is that the [HI] = 0.0M. N2O4 raised to the first power. To log in and use all the features of Khan Academy, please enable JavaScript in your browser. Also, note the coefficient for the silver ion becomes an exponent in . First, calculate the partial pressure for H 2O by subtracting the partial pressure of H 2 from the total pressure. Subsititute into the equilibrium expression and solve for K. Determine all equilibrium concentrations or partial From this the equilibrium expression for calculating And since there's an implied By the end of this section, you will be able to: Having covered the essential concepts of chemical equilibria in the preceding sections of this chapter, this final section will demonstrate the more practical aspect of using these concepts and appropriate mathematical strategies to perform various equilibrium calculations. Direct link to heavenkit022's post For the last question whe, Posted 10 hours ago. Let's say that a mixture Using this value, I used the equation for the K constant of an equilibrium: $$\mathrm{K} = \frac{[\ce{FeSCN^2+}]}{[\ce{Fe^3+}][\ce{SCN^-}]}$$, $$\mathrm{K} = \frac{\pu{6.39e-5}}{0.002^2}$$. Can corresponding author withdraw a paper after it has accepted without permission/acceptance of first author, "Signpost" puzzle from Tatham's collection. The equilibrium constant, K, describes the relative amounts of reaction species at equilibrium.The expression for K is equal to the concentrations (or partial pressures) of the products raised to their stoichiometric coefficients divided by the concentrations (or partial pressures) of the reactants raised to their stoichiometric coefficients. Calculate the equilibrium constant for the reaction. For different reactions, those rates will become equal at various places in the transformation of reactant into a product. E stands for equilibrium concentration. and so the approximation was justified. Kconly changes if the temperature at which the reaction occurs changes. PH2O = Ptotal PH2 = (0.016 0.013) atm = 0.003atm. - [Instructor] An equilibrium Write the balanced chemical equation for the reaction. To determine the units for Kc, you need to know the units of concentration used for the reactants and products in the balanced chemical equation. Let's calculate the equilibrium constant for another reaction. $\ce{[FeSCN^2+]_\text{equil}}=\pu{6.39e5 M}.$, $$\ce{[Fe^3+]_\text{equil}} = \ce{[Fe^3+]_\text{initial}} - \ce{[FeSCN^2+]_\text{equil}} $$, $$ = \pu{1.00e-3 M} - \pu{6.39e5 M} = \pu{0.94e-3 M}$$, $$\ce{[SCN-]_\text{equil}} = \ce{[SCN-]_\text{initial}} - \ce{[FeSCN^2+]_\text{equil}} $$, $$ =\pu{0.400e-3 M} - \pu{6.39e5 M} = \pu{0.336e-3 M}$$. are licensed under a, Measurement Uncertainty, Accuracy, and Precision, Mathematical Treatment of Measurement Results, Determining Empirical and Molecular Formulas, Electronic Structure and Periodic Properties of Elements, Electronic Structure of Atoms (Electron Configurations), Periodic Variations in Element Properties, Relating Pressure, Volume, Amount, and Temperature: The Ideal Gas Law, Stoichiometry of Gaseous Substances, Mixtures, and Reactions, Shifting Equilibria: Le Chteliers Principle, The Second and Third Laws of Thermodynamics, Representative Metals, Metalloids, and Nonmetals, Occurrence and Preparation of the Representative Metals, Structure and General Properties of the Metalloids, Structure and General Properties of the Nonmetals, Occurrence, Preparation, and Compounds of Hydrogen, Occurrence, Preparation, and Properties of Carbonates, Occurrence, Preparation, and Properties of Nitrogen, Occurrence, Preparation, and Properties of Phosphorus, Occurrence, Preparation, and Compounds of Oxygen, Occurrence, Preparation, and Properties of Sulfur, Occurrence, Preparation, and Properties of Halogens, Occurrence, Preparation, and Properties of the Noble Gases, Transition Metals and Coordination Chemistry, Occurrence, Preparation, and Properties of Transition Metals and Their Compounds, Coordination Chemistry of Transition Metals, Spectroscopic and Magnetic Properties of Coordination Compounds, Aldehydes, Ketones, Carboxylic Acids, and Esters, Composition of Commercial Acids and Bases, Standard Thermodynamic Properties for Selected Substances, Standard Electrode (Half-Cell) Potentials, Half-Lives for Several Radioactive Isotopes, https://openstax.org/books/chemistry-2e/pages/1-introduction, https://openstax.org/books/chemistry-2e/pages/13-4-equilibrium-calculations, Creative Commons Attribution 4.0 International License, Identify the changes in concentration or pressure that occur for chemical species in equilibrium systems, Calculate equilibrium concentrations or pressures and equilibrium constants, using various algebraic approaches. The most important step will be to first write down the equation and balance it. Species, Calculating K from Known Equilibrium Amounts, Calculating K from Initial amounts and One Known Equilibrium Note that you should account for the coefficients by using them as powers in your equilibrium equation. products over reactants. For a reaction, if you know the initial concentrations of the substances, you can calculate the equilibrium concentration. Substitute the molar equilibrium concentrations into the equation and calculate the value of Kc. Convert the given data into an ICE table, label the unknown data as 'x'. Lesson 5: Calculating equilibrium concentrations. in the balanced equation, it would be the partial Upon solving the quadratic equation, we get, x = 1.78, and x = 0.098. And since the coefficient is a one in front of carbon monoxide (Note: Water is a solute in this reaction.). So we need to write an of our reactant, N2O4. under chlorine in the ICE table. Connect and share knowledge within a single location that is structured and easy to search. So the equilibrium concentration To calculate the units for Kc, you need to know the balanced chemical equation for the reaction and the units for the concentrations of the reactants and products. If the value of Kc approaches zero, the reaction may be considered not to occur. Assume the generic reaction is aA + bB <--> cC + dD. The last step is to solve the quadratic equation to find the value of x. So the partial pressure of Learn more about Stack Overflow the company, and our products. equilibrium constant expression are equilibrium concentrations, This did not turn out to be the correct answer, but I'm not sure why. = \frac{\mathrm{Absorbance}}{\mathrm{slope}}$$, $$\mathrm{conc.} Use this information to derive terms for the equilibrium concentrations of the reactants, presenting all the information in an ICE table. Write the generic expression for the Keq for the reaction. Partial Pressure at a Temperature of 300K. Next, we plug in our Using concentrations 1 M, make up two sets of concentrations that describe a mixture of A, B, and C at equilibrium. in the balanced equation. Direct link to John#yolo's post At 4:58, what would happe, Posted a month ago. concentration of N2O4, which was 0.00140. So for the equilibrium Dr. Helmenstine holds a Ph.D. in biomedical sciences and is a science writer, educator, and consultant. goal is to calculate the equilibrium concentrations CO + H HO + CO . So from only 2.20 volts, we get a huge number for the equilibrium constant. both of our reactants. pressure of carbon dioxide times the partial And here we have the times the partial pressure of our other product, which is H2O. It only takes a minute to sign up. Apply the equilibrium constant formula KC = [C]c[D]d [A]a[B]b K C = [ C] c [ D] d [ A] a [ B] b to get a . For the example, the [H2] = 1.6 --x, [I2] = 2.4 --x and [HI] = 2x. So that's why we have 3.40 To use the equilibrium constant calculator, follow these steps: Step 1: Enter the reactants, products, and their concentrations in the input fields. Direct link to Maisha Ahmed Mithi's post Q. If this simplified approach were to yield a value for x that did not justify the approximation, the calculation would need to be repeated without making the approximation. Direct link to Richard's post The x's represent essenti, Posted a year ago. Computers, like calculators, are stupid so theyll only know to perform the calculations in the order you input them into the calculator. For the example, multiply the right-hand side of the equation to yield 3.84 -- 4x + x^2. add any carbon monoxide in the beginning, the If the values for the equilibrium constant for the forward and reverse reaction are nearly the same, then the reaction is about as likely to proceed in one direction, and the other and the amounts of reactants and products will be nearly equal. To describe how to calculate equilibrium concentrations from an equilibrium constant, we first consider a system that contains only a single product and a single reactant, the conversion of n-butane to isobutane (Equation \(\ref{Eq1}\)), for which K = 2.6 at 25C. are not subject to the Creative Commons license and may not be reproduced without the prior and express written For example, if the nitrogen concentration increases by an amount x: the corresponding changes in the other species concentrations are. [H 2] = [Br 2] = 0.010 - x = 0.010 - 0.008 = 0.002 M for each [HBr] = 2x = 2(0.008) = 0.016 M. Check your answer by substituting the equilibrium concentrations into the equilibrium expression and see if the result is the same as the equilibrium constant. equilibrium constant expression are the equilibrium partial pressures, which we can get from the ICE table. we started off with zero and we gained positive 0.20. Now we figured out that the equilibrium lies to the right, so therefore the equilibrium lies to the side that has the acid with the higher pKa value. The equilibrium constant Kc is calculated using molarity and coefficients: [A], [B], [C], [D] etc. aA +bB cC + dD. The x's represent essentially the change in concentration for the reactants and products. What is the equilibrium constant for the weak acid KHP? The Kp calculator is a tool that will convert the equilibrium constant, Kc, to Kp - the equilibrium constant in terms of partial pressure. The equilibrium constant is a dimensionless quantity (has no units). window.__mirage2 = {petok:"PLgq7hpnqIn0nasD1I4nYyQLun2fG1pVRluIe95oIWU-31536000-0"}; Save my name, email, and website in this browser for the next time I comment. We need to know two things in order to calculate the numeric value of equilibrium constant, which is symbolized by K. And since we're dealing Folder's list view has different sized fonts in different folders. We can go ahead in here and write plus X for an increase in the What are the advantages of running a power tool on 240 V vs 120 V? Where [A], [B], [C], and [D] are the molar concentrations of the reactants and products, and a, b, c, and d are the stoichiometric coefficients of the balanced chemical equation. X in here on our ICE table, or we could just write plus 0.20. of each species. Here we have our equilibrium concentrations plugged into our equilibrium constant expression, and also Kc was equal to 7.0 for this reaction at 400 Kelvin so 7.0 is plugged in . To help us find Kp, we're Why did DOS-based Windows require HIMEM.SYS to boot? This type of reaction is considered to be reversible. Next, we think about Br2 When given the equation: $$\ce{Fe^3+_{(aq)} + SCN^-_{(aq)} <=> FeSCN^2+_{(aq)}}$$ How do you calculate the equilibrium constant when given the slope of the absorbance vs concentration graph ($\pu{4317 M-1}$) and the absorbance of $\ce{FeSCN^{2+}}$ (0.276)The following information is also given: $2.000\ \mathrm{mL}$ of a $0.00200\ \mathrm{M}$ solution of $\mathrm{KSCN}$ with $5.00\ \mathrm{mL . At equilibrium the concentration of I2 is 6.61 104 M so that. state turns into 2NO2 also in the gaseous state. Parabolic, suborbital and ballistic trajectories all follow elliptic paths. We empower you to efficiently solve each new challenge and make your life better and easier. So the mole ratio of bromine ), Atomic Structure Electron Arrangement (A-Level Chemistry), Atomic Structure Electrons in Atoms (A-Level Chemistry), Atomic Structure Mass Spectrometry (A-Level Chemistry), Atomic Structure Element Isotopes (A-Level Chemistry), Atomic Structure Atomic and Mass Number (A-Level Chemistry), Atomic Structure Subatomic Particles (A-Level Chemistry), Equilibrium Constant for Homogenous Systems Le Chateliers Principle in Gas Equilibria (A-Level Chemistry), Equilibrium Constant for Homogenous Systems Gas Equilibria and Kp (A-Level Chemistry), Equilibrium Constant for Homogeneous System Changing Kp (A-Level Chemistry), Equilibrium Constant for Homogenous Systems Gas Partial Pressures (A-Level Chemistry), Acids and Bases Drawing pH Curves (A-Level Chemistry), Acids and Bases Acid-Base Indicators (A-Level Chemistry), Acids and Bases Dilutions and pH (A-Level Chemistry), Electrode Potentials and Electrochemical Cells Commercial Applications of Fuel Cells (A-Level Chemistry), Electrode Potentials and Electrochemical Cells Electrochemical Cells Reactions (A-Level Chemistry), Electrode Potentials and Electrochemical Cells Representing Electrochemical Cells (A-Level Chemistry), Electrode Potentials and Electrochemical Cells Electrode Potentials (A-Level Chemistry), Electrode Potentials and Electrochemical Cells Half Cells and Full Cells (A-Level Chemistry), Acids and Bases Titrations (A-Level Chemistry), Acids and Bases Buffer Action (A-Level Chemistry), Acids and Bases pH of Strong Bases (A-Level Chemistry), Acids and Bases Ionic Product of Water (A-Level Chemistry), Acids and Bases More Ka Calculations (A-Level Chemistry), Acids and Bases The Acid Dissociation Constant, Ka (A-Level Chemistry), Acids and Bases The pH Scale and Strong Acids (A-Level Chemistry), Acids and Bases Neutralisation Reactions (A-Level Chemistry), Acids and Bases Acid and Base Strength (A-Level Chemistry), Acids and Bases The Brnsted-Lowry Acid-Base Theory (A-Level Chemistry), Amount of Substance Percentage Atom Economy (A-Level Chemistry), Amount of Substance Calculating Percentage Yields (A-Level Chemistry), Amount of Substance Stoichiometric Calculations (A-Level Chemistry), Amount of Substance Balancing Chemical Equations (A-Level Chemistry), Amount of Substance Empirical and Molecular Formulae (A-Level Chemistry), Amount of Substance Further Mole Calculations (A-Level Chemistry), Amount of Substance- The Mole and The Avogadro Constant (A-Level Chemistry), Amount of Substance Measuring Relative Masses (A-Level Chemistry), Amount of Substance The Ideal Gas Equation (A-Level Chemistry), Periodicity Classification (A-Level Chemistry), Bonding Hydrogen Bonding in Water (A-Level Chemistry), Bonding Forces Between Molecules (A-Level Chemistry), Bonding Bond Polarity (A-Level Chemistry), Bonding Molecular Shapes (A-Level Chemistry), Bonding Predicting Structures (A-Level Chemistry), Bonding Carbon Allotropes (A-Level Chemistry), Bonding Properties of Metallic Bonding (A-Level Chemistry), Bonding Properties of Covalent Structures (A-Level Chemistry), Bonding Covalent Bonds (A-Level Chemistry), Kinetics The MaxwellBoltzmann Distribution and Catalysts (A-Level Chemistry), Kinetics The Collision Theory and Reaction Rates (A-Level Chemistry), Calculations with Equilibrium Constants (A-Level Chemistry), Chemical Equilibria applied to Industry (A-Level Chemistry), Chemical Equilibria and Le Chateliers Principle (A-Level Chemistry), Oxidation, Reduction and Redox Equations Balancing Redox Equations (A-Level Chemistry), Oxidation, Reduction and Redox Equations Redox Processes (A-Level Chemistry), Oxidation, Reduction and Redox Equations Oxidation States (A-Level Chemistry), Thermodynamic Calculations involving Free Energy (A-Level Chemistry), Thermodynamic Gibbs Free Energy (A-Level Chemistry), Thermodynamic Entropy Change Predictions (A-Level Chemistry), Thermodynamic Total Entropy Changes (A-Level Chemistry), Thermodynamic Introduction to Entropy (A-Level Chemistry), Thermodynamic Calculating Enthalpy Changes of Solution (A-Level Chemistry), Thermodynamic Enthalpy of Solution (A-Level Chemistry), Thermodynamic Enthalpy of Hydration (A-Level Chemistry), Thermodynamic Calculations involving Born-Haber Cycles (A-Level Chemistry), Thermodynamic Construction of Born-Haber Cycles (A-Level Chemistry), Rate Equations Reaction Determining Steps (A-Level Chemistry), Rate Equations Reaction Half Lives (A-Level Chemistry), Rate Equations Uses of Clock Reactions (A-Level Chemistry), Rate Equations Determining Orders of Reactions Graphically (A-Level Chemistry), Rate Equations Determining Order of Reaction Experimentally (A-Level Chemistry), Rate Equations Temperature Changes and the Rate Constant (A-Level Chemistry), Rate Equations The Rate Constant (A-Level Chemistry), Rate Equations Introduction to Orders of Reactions (A-Level Chemistry), Rate Equations The Rate Equation (A-Level Chemistry), Rate Equations Measuring Rate of Reaction (A-Level Chemistry), Periodicity Trends Along Period 3 (A-Level Chemistry), Uses of Group 2 Elements and their Compounds (A-Level Chemistry), Reactions of Group 2 Elements (A-Level Chemistry), Group 2, The Alkaline Earth Metals (A-Level Chemistry), The Halogens -Halide Ions and their Reactions (A-Level Chemistry), The Halogens Disproportionation Reactions in Halogens (A-Level Chemistry), The Halogens Reactions with Halogens (A-Level Chemistry), The Halogens Group 7, The Halogens (A-Level Chemistry), Properties of Period 3 Elements Properties of Period 3 Compounds (A-Level Chemistry), Properties of Period 3 Elements Reactivity of Period 3 Elements (A-Level Chemistry), Transition Metals Autocatalysis of Transition Metals (A-Level Chemistry), Transition Metals Transition Metals as Homogeneous Catalysts (A-Level Chemistry), Transition Metals Transition Metals as Heterogeneous Catalysts (A-Level Chemistry), Transition Metals Examples of Redox Reactions in Transition Metals (A-Level Chemistry), Transition Metals Iodine-Sodium Thiosulfate Titrations (A-Level Chemistry), Transition Metals Carrying Titrations with Potassium Permanganate (A-Level Chemistry), Transition Metals Redox Titrations (A-Level Chemistry), Transition Metals Redox Potentials (A-Level Chemistry), Transition Metals Redox Reactions Revisited (A-Level Chemistry), Transition Metals Ligand Substitution Reactions (A-Level Chemistry), Reactions of Ions in Aqueous Solutions Metal Ions in Solution (A-Level Chemistry), Introduction to Organic Chemistry Structural Isomers (A-Level Chemistry), Introduction to Organic Chemistry E/Z Isomerism (A-Level Chemistry), Introduction to Organic Chemistry Reaction Mechanisms in Organic Chemistry (A-Level Chemistry), Introduction to Organic Chemistry General Formulae (A-Level Chemistry), Introduction to Organic Chemistry Introduction to Functional Groups (A-Level Chemistry), Introduction to Organic Chemistry Naming and Representing Organic Compounds (A-Level Chemistry), Aromatic Chemistry Friedel-Crafts Acylation and Alkylation (A-Level Chemistry), Aromatic Chemistry Halogenation Reactions in Benzene (A-Level Chemistry), Aromatic Chemistry Electrophilic Substitution Reactions in Benzene (A-Level Chemistry), Aromatic Chemistry Improved Benzene Model (A-Level Chemistry), Aromatic Chemistry Introduction to Benzene (A-Level Chemistry), Amines Properties and Reactivity of Amines (A-Level Chemistry), Amines Amine Synthesis (A-Level Chemistry), Amines Introduction to Amines (A-Level Chemistry), Polymer Biodegradability (A-Level Chemistry), Condensation Polymers (A-Level Chemistry), Amino Acids, Proteins and DNA DNA Replication (A-Level Chemistry), Amino Acids, Proteins and DNA DNA (A-Level Chemistry), Amino Acids, Proteins and DNA Enzyme Action (A-Level Chemistry), Amino Acids, Proteins and DNA Structure of Proteins (A-Level Chemistry), Amino Acids, Proteins and DNA Structure of Amino Acids (A-Level Chemistry), Organic Synthesis Considerations in Organic Synthesis (A-Level Chemistry), Organic Synthesis Organic Synthesis: Aromatic Compounds (A-Level Chemistry), Organic Synthesis Organic Synthesis: Aliphatic Compounds (A-Level Chemistry), Analytical Techniques High Resolution H NMR (A-Level Chemistry), Analytical Techniques Types of NMR: Hydrogen (A-Level Chemistry), Analytical Techniques Types of NMR: Carbon 13 (A-Level Chemistry), Analytical Techniques NMR Samples and Standards (A-Level Chemistry), Analytical Techniques Nuclear Magnetic Resonance Spectroscopy (A-Level Chemistry), Analytical Techniques Different Types of Chromatography (A-Level Chemistry), Analytical Techniques Chromatography (A-Level Chemistry), Alkanes Obtaining Alkanes (A-Level Chemistry), Alkanes Alkanes: Properties and Reactivity (A-Level Chemistry), Halogenoalkanes Environmental Impact of Halogenalkanes (A-Level Chemistry), Halogenoalkanes Reactivity of Halogenoalkanes (A-Level Chemistry), Halogenoalkanes Introduction to Halogenoalkanes (A-Level Chemistry), Alkenes Addition Polymerisation in Alkenes (A-Level Chemistry), Alkenes Alkene Structure and Reactivity (A-Level Chemistry), Alcohols Industrial Production of Alcohols (A-Level Chemistry), Alcohols Alcohol Reactivity (A-Level Chemistry), Alcohols Alcohol oxidation (A-Level Chemistry), Alcohols Introduction to Alcohols (A-Level Chemistry), Organic Analysis Infrared (IR) Spectroscopy (A-Level Chemistry), Organic Analysis Identification of Functional Groups (A-Level Chemistry), Aldehydes and Ketones Reactions to Increase Carbon Chain Length (A-Level Chemistry), Aldehydes and Ketones Testing for Carbonyl Compounds (A-Level Chemistry), Aldehydes and Ketones Reactivity of Carbonyl Compunds (A-Level Chemistry), Aldehydes and Ketones Carbonyl Compounds (A-Level Chemistry), Carboxylic Acids and Derivatives Structure of Amides (A-Level Chemistry), Carboxylic Acids and Derivatives Acyl Groups (A-Level Chemistry), Carboxylic Acids and Derivatives Properties and Reactivity of Esters (A-Level Chemistry), Carboxylic Acids and Derivatives Properties and Reactivity of Carboxylic Acids (A-Level Chemistry), Bonding Ion Formation (A-Level Chemistry), Bonding Properties of Ionic Bonding (A-Level Chemistry), The Halogens Testing for Ions (A-Level Chemistry), Organic Synthesis Practical Purification Techniques (A-Level Chemistry), Organic Synthesis Practical Preparation Techniques (A-Level Chemistry), Thermodynamic Enthalpy Key Terms (A-Level Chemistry), Thermodynamic Lattice Enthalpies (A-Level Chemistry), Precipitation Reactions of Metal Ions in Solution (A-Level Chemistry), Transition Metals Colour in Transition Metal Ions (A-Level Chemistry), Transition Metals Optical Isomerism in Complex Ions (A-Level Chemistry), Transition Metals Cis-Trans Isomerism in Complex Ions (A-Level Chemistry), Transition Metals Complex Ion Shape (A-Level Chemistry), Transition Metals Ligands (A-Level Chemistry), Aromatic Chemistry Reactivity of Substituted Benzene (A-Level Chemistry), Aromatic Chemistry Benzene Nomenclature (A-Level Chemistry), Analytical Techniques Deuterium use in H NMR (A-Level Chemistry), https://www.medicmind.co.uk/medic-mind-foundation/.
how to calculate equilibrium concentration without kc